The muon has the same charge as an electron b | vedclass

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(B) The binding energy of a hydrogen-like atom in the ground state is given by the formula $E_n = -\frac{m e^4}{8 \epsilon_0^2 h^2 n^2}$,where $m$ is

Vedclass · Accepted Answer

$|E_{B\mu}| \approx 207|E_{Be}|$

Vedclass · Answer

(B) The binding energy of a hydrogen-like atom in the ground state is given by the formula $E_n = -\frac{m e^4}{8 \epsilon_0^2 h^2 n^2}$,where $m$ is the mass of the orbiting particle.Since the charge of the muon is the same as the electron,the binding energy is directly proportional to the mass of the particle $(E \propto m)$.Given that the mass of the muon $m_{\mu} = 207 m_e$,the binding energy of the muonic hydrogen atom is $E_{B\mu} = 207 E_{Be}$.Therefore,$|E_{B\mu}| \approx 207 |E_{Be}|$. The closest option provided is $207|E_{Be}|$,which corresponds to option $B$.

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